Chapter Notes · 9th Class Physics 11 min readUpdated 4 October 2026

9th Class Physics Chapter 1 Notes: Physical Quantities and Measurements (Punjab Board)

Chapter 1 of 9th class Physics is about measurement. A physical quantity is anything that can be measured, and every measurement needs a number and a unit. The chapter covers the seven SI base units, prefixes, scientific notation, the vernier caliper and screw gauge, and significant figures. Use these notes for quick revision before a test.

Chapter at a glance

TopicWhat you must be able to do
Physical quantitiesDefine them, separate base and derived quantities, give examples
SI unitsWrite the seven base units with symbols; build derived units
Prefixes and scientific notationConvert units and write numbers as a × 10ⁿ
Measuring instrumentsMeter rule, vernier caliper, screw gauge, balance, stopwatch, measuring cylinder
Zero error and least countFind them and correct a reading
Significant figuresCount them and round answers properly
Accuracy and precisionExplain the difference with an example

The Punjab textbook for this class is the same for every board, so these notes help students of the nine boards below. Your teacher may mark a small topic as not included in your school, so follow your own textbook and date sheet for the final list.

Students of these nine Punjab boards can use these notes:

  • BISE Lahore
  • BISE Rawalpindi
  • BISE Gujranwala
  • BISE Faisalabad
  • BISE Multan
  • BISE Sargodha
  • BISE Sahiwal
  • BISE Dera Ghazi Khan
  • BISE Bahawalpur

Key concepts and definitions

  • Physics is the branch of science that studies matter, energy and the way they interact. Its main branches include mechanics, heat, light, sound, electricity and magnetism, and atomic and nuclear physics.
  • Physical quantity: a quantity that can be measured. A measurement has a number (magnitude) and a unit. Length, mass, time and temperature are physical quantities. Honesty or beauty cannot be measured, so they are not physical quantities.
  • Base quantities are independent quantities that are taken as the starting point of measurement. Derived quantities are formed from the base quantities, for example area, volume, speed and density.
  • SI (International System of Units) is the system of units agreed for use all over the world. It is based on the metre, kilogram and second along with four other base units.
  • Scientific notation writes a number as a × 10ⁿ, where a is at least 1 and less than 10, and n is a whole number.
  • Least count is the smallest value an instrument can measure correctly.
  • Zero error: the reading an instrument shows when it should read zero. It must be removed from every observation.
  • Accuracy tells how close a measurement is to the true value. Precision tells how close repeated readings are to each other.
  • Error is the difference between the measured value and the true value. Faulty instruments and zero error give systematic errors; reaction time with a stopwatch gives random errors.

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SI base units and prefixes

Base quantitySI unitSymbol
Lengthmetrem
Masskilogramkg
Timeseconds
Electric currentampereA
TemperaturekelvinK
Amount of substancemolemol
Luminous intensitycandelacd

Prefixes make very large or very small values easy to write:

PrefixSymbolPower of ten
gigaG10⁹
megaM10⁶
kilok10³
centic10⁻²
millim10⁻³
microµ10⁻⁶
nanon10⁻⁹
picop10⁻¹²

Note that the kilogram, not the gram, is the base unit of mass. Some derived units you will use later are the newton (N = kg m s⁻²), the pascal (Pa = N m⁻²) and the joule (J = N m).

Formulas and rules to remember

RuleFormulaSymbols and units
Scientific notationa × 10ⁿ1 ≤ a, a less than 10; n is an integer
Least count of vernier caliperLC = 1 MSD − 1 VSDMSD, VSD: main and vernier scale divisions (mm or cm)
Vernier readingMSR + (VSR × LC)MSR: main scale reading; VSR: coinciding vernier division
Least count of screw gaugeLC = pitch ÷ number of circular divisionspitch in mm
Screw gauge readinglinear scale + (circular scale × LC)mm
Corrected readingobserved reading − zero errorzero error carries its sign
Densityρ = m ÷ Vρ in kg m⁻³, m in kg, V in m³
Volume of a cylinderV = πr²hr radius, h height, in m
Volume of a solid by displacementV = V₂ − V₁V₁ initial and V₂ final liquid level, in cm³

Instruments explained step by step

Where the least count of a vernier caliper comes from

  1. Let one main scale division (MSD) be 1 mm.
  2. Suppose 10 vernier scale divisions (VSD) fit exactly into 9 MSD, which is 9 mm.
  3. Then 1 VSD = 9 ÷ 10 = 0.9 mm.
  4. Least count = 1 MSD − 1 VSD = 1 − 0.9 = 0.1 mm = 0.01 cm.

The general result is LC = (smallest main scale division) ÷ (number of vernier divisions).

Taking a vernier reading

  1. Close the jaws and note the zero error first.
  2. Place the object between the jaws and read the main scale just before the vernier zero (MSR).
  3. Find the vernier line that exactly meets a main scale line. Call its number n.
  4. Reading = MSR + n × LC. Then subtract the zero error.

With 10 vernier divisions, a vernier zero to the right of the main zero gives a positive zero error of +n × LC, where n is the coinciding line. If the vernier zero is to the left and the m-th line coincides, the zero error is −(10 − m) × LC. The corrected reading is always observed reading minus zero error, so a negative error is added.

Screw gauge

The pitch is the distance the spindle moves forward in one full turn. A common screw gauge has a pitch of 1 mm and 100 circular divisions, so LC = 1 ÷ 100 = 0.01 mm. If the circular scale reads n divisions when the gap is closed and n is small, the error is +n × LC. If it reads close to 100, for example 97, the error is −(100 − 97) × LC = −0.03 mm.

Other instruments

  • Meter rule: least count 1 mm. Keep your eye straight above the mark to avoid parallax error.
  • Physical balance: compares the unknown mass with standard masses.
  • Stopwatch: measures a time interval. A digital one often reads to 0.01 s, but your reaction time is usually larger than that.
  • Measuring cylinder: read the liquid level at eye level, at the lowest point of the curved surface for water. The volume of an irregular solid that sinks is V₂ − V₁.

Significant figures

  • All non-zero digits are significant.
  • Zeros between non-zero digits are significant (3004 has four).
  • Leading zeros are not significant (0.0042 has two).
  • Trailing zeros after a decimal point are significant (25.00 has four).
  • In multiplication and division, keep as many significant figures as the least precise value has.
  • In addition and subtraction, keep as many decimal places as the value with the fewest decimal places.

Solved numericals

Numerical 1: vernier caliper

A vernier caliper has LC = 0.01 cm. For a cylinder, the main scale reads 2.4 cm and the 6th vernier line coincides. With the jaws closed, the 2nd vernier line coincides. Find the corrected diameter.

Zero error = +2 × 0.01 = +0.02 cm. Observed reading = 2.4 + 6 × 0.01 = 2.46 cm. Corrected reading = 2.46 − 0.02 = 2.44 cm.

Numerical 2: screw gauge

A screw gauge has pitch 1 mm and 100 circular divisions. For a wire, the linear scale shows 3 mm and the circular scale shows 27 divisions. With the gap closed the circular scale reads 97. Find the diameter.

LC = 1 ÷ 100 = 0.01 mm. Zero error = −(100 − 97) × 0.01 = −0.03 mm. Observed reading = 3 + 27 × 0.01 = 3.27 mm. Corrected reading = 3.27 − (−0.03) = 3.30 mm.

Numerical 3: scientific notation and conversions

  1. 0.00056 g in kg: 0.00056 g = 5.6 × 10⁻⁴ g. Since 1 g = 10⁻³ kg, the mass is 5.6 × 10⁻⁴ × 10⁻³ = 5.6 × 10⁻⁷ kg.
  2. 72 km/h in m/s: 72 × 1000 ÷ 3600 = 20 m/s.
  3. 3 × 10⁸ m/s in km/h: 3 × 10⁸ × 3600 ÷ 1000 = 3 × 10⁸ × 3.6 = 10.8 × 10⁸ = 1.08 × 10⁹ km/h.

Numerical 4: significant figures

Counts: 0.00450 has 3; 3004 has 4; 25.00 has 4; 6.02 × 10²³ has 3. A rectangle measures 4.5 m by 2.34 m. Area = 4.5 × 2.34 = 10.53 m². The value 4.5 has 2 significant figures, so the answer is 11 m². For addition, 12.52 + 1.7 = 14.22, and the least number of decimal places is one, so the answer is 14.2.

Numerical 5: density with unit conversion

A block of 10 cm × 5.0 cm × 4.0 cm has a mass of 540 g. Find its density in kg m⁻³.

Volume = 10 × 5.0 × 4.0 = 200 cm³. Density = 540 ÷ 200 = 2.7 g cm⁻³. Because 1 g cm⁻³ = 10⁻³ kg ÷ 10⁻⁶ m³ = 10³ kg m⁻³, the density is 2700 kg m⁻³.

Common mistakes

  • Writing the SI unit of mass as the gram. It is the kilogram.
  • Forgetting the sign of the zero error, or subtracting a negative error instead of adding it.
  • Choosing the vernier line that is nearest the zero instead of the one that meets a main scale line exactly.
  • Counting leading zeros as significant figures.
  • Writing 12 × 10³ as scientific notation. The first number must be between 1 and 10.
  • Mixing µ (micro, 10⁻⁶) with m (milli, 10⁻³).
  • Using cm in one place and m in another in the same formula.
  • Reading a measuring cylinder from above or below eye level.

Questions to practise

Short questions

  1. Define a physical quantity and give two examples.
  2. Differentiate between base and derived quantities.
  3. Write the seven SI base quantities with their units and symbols.
  4. Why are prefixes used? Write the value of kilo, milli, micro and nano.
  5. Express 0.00025 s and 4 500 000 m in scientific notation.
  6. What is the least count of an instrument? How is it found for a vernier caliper?
  7. What is zero error? How is a reading corrected for it?
  8. Define the pitch of a screw gauge.
  9. State the rules for zeros in significant figures.
  10. Differentiate between accuracy and precision.
  11. How can you find the volume of a small irregular stone with a measuring cylinder?

Long questions

  1. Describe a vernier caliper. Explain how to find its least count, take a reading and correct the zero error.
  2. Describe a screw gauge and explain how to measure the diameter of a wire with it.
  3. Explain the SI system with examples of base and derived units. Write the units of density and pressure in base units.
  4. Explain significant figures and the rules for using them in calculations, with examples.

Numericals to try

  1. Convert 2.5 km into metres and into millimetres. Write both in scientific notation.
  2. A vernier caliper has 20 vernier divisions equal to 19 main scale divisions of 1 mm each. Find its least count.
  3. A screw gauge has a pitch of 0.5 mm and 50 circular divisions. Find its least count and the reading for 4 linear divisions and 18 circular divisions.
  4. Find the number of significant figures in 0.0070, 1.050 and 800.
  5. A solid of mass 0.27 kg occupies 100 cm³. Find its density in kg m⁻³.

Practice MCQs

Try these first. The answer key is at the end of the article.

  1. Which of the following is a base quantity?
    A) Force

    B) Speed

    C) Time

    D) Area
  2. The SI unit of electric current is
    A) volt

    B) ampere

    C) ohm

    D) coulomb
  3. 5.6 × 10⁻³ m is equal to
    A) 0.56 mm

    B) 5.6 mm

    C) 56 mm

    D) 560 mm
  4. One main scale division is 1 mm and 10 vernier divisions equal 9 main scale divisions. The least count is
    A) 1 mm

    B) 0.5 mm

    C) 0.1 mm

    D) 0.01 mm
  5. The number of significant figures in 0.0305 is
    A) 2

    B) 3

    C) 4

    D) 5
  6. The SI unit of density in base units is
    A) kg m⁻²

    B) kg m⁻³

    C) g cm⁻³

    D) kg m³
  7. The prefix nano stands for
    A) 10⁻³

    B) 10⁻⁶

    C) 10⁻⁹

    D) 10⁻¹²
  8. A screw gauge has a pitch of 1 mm and 50 divisions on the circular scale. Its least count is
    A) 0.5 mm

    B) 0.2 mm

    C) 0.02 mm

    D) 0.002 mm

Preparation strategy

  1. Day 1: learn the seven base units, symbols and prefixes. Write them from memory.
  2. Day 2: practise the vernier caliper with the least count derivation and three readings, including a zero error.
  3. Day 3: do the same for the screw gauge.
  4. Day 4: do scientific notation, conversions and significant figures.
  5. Day 5: attempt the chapter MCQs and short questions, then redo the ones you missed.

For the complete picture of the class, read the 9th class Physics textbook guideand the 9th class Physics pairing scheme.

Diagram ideas

  • Labelled vernier caliper. Alt text: "Vernier caliper with the jaws, main scale, vernier scale, depth rod and locking screw labelled."
  • Vernier reading example. Alt text: "Close-up of a vernier scale with the sixth line meeting a main scale line, showing how the reading is added."
  • Zero error cases. Alt text: "Three closed vernier calipers showing no error, positive zero error and negative zero error."
  • Labelled screw gauge. Alt text: "Screw gauge with the frame, anvil, spindle, linear scale, circular scale and ratchet labelled."
  • Measuring cylinder. Alt text: "Measuring cylinder with water, an eye at the level of the lower meniscus and a stone being lowered in."
  • SI table. Alt text: "Chart of the seven SI base quantities with their units and symbols."

MCQ answer key

  1. C. Length, mass and time are base quantities. Force, speed and area are derived.
  2. B. The ampere (A) is the base unit of electric current.
  3. B. 10⁻³ m is 1 mm, so 5.6 × 10⁻³ m is 5.6 mm.
  4. C. 1 VSD = 0.9 mm, so least count = 1 − 0.9 = 0.1 mm.
  5. B. Leading zeros do not count. The digits 3, 0 and 5 give three significant figures.
  6. B. Density is mass divided by volume, so kg / m³ = kg m⁻³.
  7. C. Nano means one billionth, 10⁻⁹.
  8. C. Least count = pitch / divisions = 1 mm / 50 = 0.02 mm.

Frequently asked questions

What is Chapter 1 of 9th class Physics about?

Chapter 1, Physical Quantities and Measurements, explains what a physical quantity is, the seven base SI units, prefixes, scientific notation, the use of measuring instruments such as the vernier caliper and screw gauge, and significant figures. It is the base for every numerical in the rest of the book.

What is the difference between a base quantity and a derived quantity?

A base quantity is an independent quantity chosen as a starting point, such as length, mass and time. A derived quantity is made by combining base quantities, such as speed (length divided by time) or density (mass divided by volume).

How do I find the least count of a vernier caliper?

Least count is the value of one smallest main scale division divided by the number of divisions on the vernier scale. If one main scale division is 1 mm and the vernier has 10 divisions, the least count is 0.1 mm, which is 0.01 cm.

Which numericals come from Chapter 1 in the exam?

Typical numericals are unit and prefix conversions, scientific notation, finding the least count and a corrected reading of a vernier caliper or screw gauge, and counting or rounding significant figures. Practise all five types.

Are these notes enough for the paper?

They are a revision guide. Always read your own Punjab textbook and its exercises, because the paper is set from the textbook and the learning outcomes. Use these notes to revise and to practise, and ask your teacher about any topic your school has marked as not included.

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